Two objects A and B are thrown upward simultaneously with the same speed. The mass of A is greater than that of B. Suppose the air exerts a constant and equal force of resistance on the two bodies.

Question

KollegeApply · Accepted Answer

A will go higher than B. Let the air exert a constant resistance force = F (in downward direction). Acceleration of particle A in downward direction due to air resistance, aA = F/mA. Acceleration of particle B in downward direction due to air resistance, aB = F/mB. mA > mB aA < aB S = ut + $\frac{1}{2}$a t^2 So, H_A = ut - $\frac{1}{2}$( a_A + g) t^2 H_B = ut - $\frac{1}{2}$( a_B + g) t^2 H_A > H_B Therefore, A will go higher than B.

AChoose Your Answer