When a glass slab of refractive index 1.5 is placed on a cross marked on paper, the cross appears to be raised by 2 cm. The thickness of the slab is ______.

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When a glass slab of refractive index 1.5 is placed on a cross marked on paper, the cross appears to be raised by 2 cm. The thickness of the slab is 6 cm. Explanation: Given, n = 1.5 and d = 2 cm The apparent raised height (d) of the cross is related to the thickness (t) of the glass slab and its refractive index (n) by the formula: d = t(1 - 1/n) Rearranging to find (t): t = d/(1 - 1/n) = 2/(1 - $\frac{1}{1}$.5) = 2/(1 - $\frac{2}{3}$) = 2/($\frac{1}{3}$) = 6 cm

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