Which of the following particles will have minimum frequency of revolution when projected with the same velocity perpendicular to a magnetic field?

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KollegeApply · Accepted Answer

Li+ Time period of the revolution of the particle, T = (2pim)/(qB) As frequency is the reciprocal of time period, so f =(qB)/(2pim) The charge on all the four particles is same. But the mass is maximum for Li+. So, it will have the smallest frequency of revolution.

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